So did I, Lord T. In a right-angled triangle, one of the interior angles is always 90 degrees. The sum of all interior angles in any triangle is 180 degrees, so the other two angles must add up to 90 degrees. So in this case for the large triangle you have 180 – (90 + 55) = 35. For the small triangle 180 – (35 + 85) = 120. So X must be 60 degrees.
60°
If the unmarked angle (far right) is 45, then it would be 45 plus 90, taken from 180.
The unmarked acute angle on the far right is 180 -90-55=35°. [Large triangle]
Then ‘X’ = 180-90-35=55° [Small triangle.]
Alternately the two trianges are congruent, [two common angles, the third angles must be equal] : thus ‘X’ must equal 55°
……
JH: Too clever by arf, DAD.
I make it 60.
All angles added together in a triangle = 180.
So 180-55 gives you the far right as 35
Middle of the triangle =180 – 95. It isn’t a right angle giving top relevant angle as 85
Therefore x = 180 – (85 + 35) = 60
So did I, Lord T. In a right-angled triangle, one of the interior angles is always 90 degrees. The sum of all interior angles in any triangle is 180 degrees, so the other two angles must add up to 90 degrees. So in this case for the large triangle you have 180 – (90 + 55) = 35. For the small triangle 180 – (35 + 85) = 120. So X must be 60 degrees.
There ya go.